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Usually gravity assist maneuvers are used to accelerate a probe without expending propellant. But could gravity assist maneuver be used to brake and insert into orbit?

Is there a formula to use for speed-deltaV-thrust that would be required at closest-approach for braking? consider the case of an interstellar probe to be able to brake in a target star using gravity assist.

lurscher
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    I'm new here, but I believe it's brake OR insert into orbit. Gravity is an attractive force so you need to be moving away from a star in order to decelerate, which isn't an orbit trajectory. In contrast, in order to enter orbit you will have to encounter an acceleration due to gravity. – Wutnaut Dec 04 '14 at 16:56
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    @Wutnaut "Gravity assist" is somewhat of a misnomer. What is going on is actually a transfer of momentum between a planetary or stellar mass object and the much smaller mass of a space vehicle. So, yes, it can be used for braking. – Jerard Puckett Dec 04 '14 at 17:06
  • Sure, just approach from the opposite direction. – gerrit Dec 04 '14 at 17:12
  • @JerardPuckett I appreciate the correction. Can you give an example how gravity can be used for braking? I'm having a hard time visualizing it. – Wutnaut Dec 04 '14 at 17:17
  • @Wutnaut as gerrit said, approach the object in a direction opposite its orbital direction, so that its gravity bleeds off your momentum. – Jerard Puckett Dec 04 '14 at 17:27
  • @JerardPuckett I was assuming the question was about entering the orbit of the same object you're using to brake. So I'm clear: you cannot use a celestial body as a 'gravity brake' AND enter it's orbit without propellant, right? – Wutnaut Dec 04 '14 at 17:40
  • @Wutnaut AFAIK, if your approach vector and velocity are constrained properly, you could achieve orbit without a burn. However, it's hard to imagine you wouldn't need some, perhaps more than one, course corrections. – Jerard Puckett Dec 04 '14 at 17:47
  • so basically, aim for the exit orbit with least angular momentum relative to star CoM, and wait for star's gravity to do its job? does that means that the maximum velocity is constrained by the star's escape velocity? – lurscher Dec 04 '14 at 17:49
  • A hyperbolic orbit with regard to the sun would have the same exit velocity as the velocity coming in. It is direction that is changed. However a hyperbolic orbit with regard to one of the gas giants might change direction so a hyperbolic orbit with regard to the sun becomes an elliptical capture orbit. – HopDavid Dec 04 '14 at 17:55

3 Answers3

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The speed of the probe doesn't change with regard to the assisting body. It is direction that is changed.

If a hyperbolic orbit about the sun comes in with a Vinfinity of 5 km/s, it will exit with a Vinfinity of 5 km/s.

Unless it happens to swing by a planet. From the planet's point of view incoming and outgoing speed are also the same. Again, it's direction that is changed. But a direction change with regard to a planet could be a speed change with regard to the sun. Thus a fly by of one of the gas giants might slow a hyperbolic about the sun to an elliptical capture orbit about the sun.

Here is an illustration of how a lunar swing by might change an hyperbolic asteroid's path to a capture about the earth:

enter image description here

At the moon's neighborhood, earth escape velocity is around 1.5 km/s. Thus dropping the asteroid's speed from 1.98 wrt earth to 1.14 wrt earth brings the rock into an elliptical capture orbit about the earth.

In a similar fashion, a swing by of one of the gas giants might trap an object from outside our solar system into an elliptical capture orbit about the sun.

HopDavid
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You can not use a gravity assist around a body to enter orbit around the same body, because a gravity assist doesn't change your velocity relative to the body you fly by. It only changes your velocity relative to other bodies.

However, you can perform a gravity assist around a satellite of a body to enter the orbit of that body. You could, for example, perform a gravity assist around Ganymede to enter Jupiter orbit.

Philipp
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  • -1 a gravity assist doesn't change your velocity relative to the body you fly by is completely incorrect. The total energy of the two body system is what doesn't change. –  Jul 21 '16 at 09:09
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The maneuver you're looking for is not called a gravity assist. A gravity assist can be conceptualized as a 3-body problem: body 1 (your spacecraft) picks up or drops off angular momentum that body 2 (the planet/moon) has in relation to body 3 (the body being orbited).

No, you're not an idiot, this is actually a common pitfall encountered by many student astronavigators.

The maneuver used to get captured into an orbit of your target planet or star is technically an Oberth maneuver, but is usually referred to as an orbital insertion burn. In your case, as you enter your stellar system's sphere of influence, you adjust your course to approach the star on a hyperbolic trajectory. You'll want to make the periapsis of that trajectory as close as possible to the star itself, but not so close that you burn up. Do your burn during your closest approach (that's the most efficient time) to change that hyperbola to an ellipse, and you have capture. You'll probably want to have a secondary burn at apoapsis to circularize your orbit to avoid repeatedly roasting your craft.

Of course, if your target star has a gas giant in a suitable orbit, you might want to design your mission to use a gravity assist after all.

Jerard Puckett
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