When I lift my hands above my head, my center of mass moves upwards. What force causes my center of mass to move upwards?
We know that $$\vec{F}_{\text{net external over all particles}} = M\ddot{\vec{R}}_{cm} \tag{1}$$ where $M$ is the total mass and $\vec{R}_{cm}$ is the center of mass of the system. This is the equation of motion for the center of mass. It says that only external forces determine the trajectory of a center of mass.
Thoughts :
When I lift my arms above my head, this force could be an external force. If so, my question disappears. However, a new question arises which is: where is this external force coming from? It's source/location? (One would think the food that we eat... However I'm still confused how an external force can reside within our bodies/midochondria).
Now equation $(1)$ assumes that all internal forces are equal and opposite. If we assume this is not the case, equation $(1)$ becomes
$$ \sum_{\alpha}\sum_{\beta\neq\alpha}\vec{F}_{\alpha\beta} + \sum_{n} \vec{F}_{\text{n}}\;^{\text{external}} = M \ddot{\vec{R}}_{cm}$$
where the double sum takes care of internal forces and runs over all particles (the force on particle $\alpha$ due to all other $\beta$). So maybe it's the internal forces which allow my center of mass to shift upwards when I raise my arms. However, I'm still confused what this would even mean.
With play-doh if you deform the shape, it's easy to see why the center of mass would move. You are applying an external force to the play-doh. The human body is much more complicated, but I was wondering if I'm missing something in my above logic. (there is also a subtlety between a discrete and continuous mass distribution - but I think the equations still apply - or maybe they dont)