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This is not so much a trick as it is spplot()'s nifty built-in functionality. spplot()’s ability to scale legend swatches (to match classification break ranges) serves as a useful pedagogical tool when discussing attribute data distribution and classification types. Combining cumulative distribution plots with the maps helps in this endeavor.

The students only need to modify a few script parameters to explore classification types and data transformation effects. This is usually their first foray into R in what is a mostly ArcGIS centric course.
Here's a code snippet:
library(rgdal) # Loads SP package by default
NE = readOGR(".", "NewEngland") # Creates a SpatialPolygonsDataFrame class (sp)
library(classInt)
library(RColorBrewer)
pal = brewer.pal(7,"Greens")
brks.qt = classIntervals(NE$Frac_Bach, n = 7, style = "quantile")
brks.jk = classIntervals(NE$Frac_Bach, n = 7, style = "jenks")
brks.eq = classIntervals(NE$Frac_Bach, n = 7, style = "equal")
Example of one of the map plots
spplot(NE, "Frac_Bach",at=brks.eq$brks,col.regions=pal, col="transparent",
main = list(label="Equal breaks"))
Example of one of the cumulative dist plots
plot(brks.eq,pal=pal,main="Equal Breaks")
Ref: Applied Spatial Data Analysis with R (R. Bivand, E Pebesma & V. Gomez-Rubio)
e <- extent(x[4:7] + c(-0.001, 0.001, -0.001, 0.001))ad I get an error messageError: c("x", "y") %in% names(x) is not all TRUE.x[4:7]seems fine though; any thoughts on what the problem might be? – djq Nov 25 '11 at 17:07x <- geocode('110 George Street, Bathurst, NSW, Australia')returnsZERO_RESULTSfor example, and when I use an example that returns a lat/long, the functione <- extent(x[4:7] + c(-0.001, 0.001, -0.001, 0.001)) also fails.– djq Nov 27 '11 at 21:18extentrequires a vector of numbers. So this workse <- extent(c(x[,4], x[,5], x[,6], x[,7]) + c(-0.001, 0.001, -0.001, 0.001)). – djq Nov 27 '11 at 21:29e <- extent(as.numeric(x[4:7]) + c(-0.001, 0.001, -0.001, 0.001))– snth Nov 28 '11 at 08:50