Use output from command line as a parameter for a command

Question

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How to replace a command with the result of another in linux?

I'm able to parse my command output so it only shows the file name that I'm interested.

My question is, I want to be able to take the output and use it as a parameter for svn diff.

svn diff /filename_from_output/

set the filename from output to a variable and pass that variable in to your command. foo = some command; some_other_command $foo; — Scott C Wilson, Apr 17 '12 at 19:09

score 7 · Accepted Answer · answered Apr 17 '12 at 19:17

7

Normally, the following should work:

svn diff "$(your-command)"

$() is simple bash command substitution. The output of the command enclosed in $() will be substituted in the outer command.

answered Apr 17 '12 at 19:17

slhck

score 0 · Answer 2 · answered Apr 18 '12 at 00:07

0

I usually enclose the command in backquotes. This works in tcsh too... I am just used to doing it this way because I write a bit of Perl.

svn diff `whatname.sh`

Or if the output can contain spaces:

svn diff "`whatname.sh`"

answered Apr 18 '12 at 00:07

paddy

2 Answers2