Is there a way to make a printing string literally in C, it has?

Question

fprintf(fptr, "#NoEnv SetWorkingDir %A_ScriptDir% CoordMode, Mouse, Window SendMode Input #SingleInstance Force SetTitleMatchMode 2 #WinActivateForce SetControlDelay 1 SetWinDelay 0 SetKeyDelay -1 SetMouseDelay -1 SetBatchLines -1 Loop { Sleep, 10 CoordMode, Pixel, Screen PixelSearch, FoundX, FoundY, 1324, 589, 1324, 589, 0x00786A, 0, RGB If ErrorLevel = 0 { Sleep, 1000 Click, 696, 728 Left, 1 Sleep, 10 Sleep, 300 Click, 775, 726 Left, 1 Sleep, 10 Sleep, 300 Click, 1273, 590 Left, 1 Sleep, 10 Return } else {  sleep, 4000 Send {f5} sleep, 3000 Click, 1324, 589, 0 sleep, 10 }} Return")"");

Here is my code, not sure if it would work for what I'm doing, but it believes that the % and other stuff in the quotations are meant to be variables or whatever, how do I make it so it ignores all of that and just prints it?

You also need to escape the embedded quotes with `\"` – Barmar Apr 08 '21 at 21:06 — Barmar, Apr 08 '21 at 21:06

score 4 · Answer 1 · answered Apr 08 '21 at 21:00

4

fprintf stands for File Print Formatted.

In order to print unformatted, consider using fputs

answered Apr 08 '21 at 21:00

Irad Ohayon

174
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I see!! Thanks, I did something else, but I'll keep that in mind. – TheAwesome444 Apr 08 '21 at 23:04

score 0 · Answer 2 · edited Apr 08 '21 at 21:05

0

You need to escape the %. You can do this by writing %% instead of %.

edited Apr 08 '21 at 21:05

Barmar

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answered Apr 08 '21 at 20:59

K. Sean

57
5

Is there a way to make a printing string literally in C, it has?

2 Answers2