I'm using yadcf filter plugin and the code is as follows...
HTML:
<table id="myTable">
<thead>
<tr>
<th>xyz</th>
</tr>
</thead>
<tbody>
<tr>
<td>
<span>
<span id="eg1">abc</span>
<span id="eg2" style="display: none;">fgd abc wew</span>
</span>
</td>
</tr>
<tr>
<td>
<span>
<span id="eg3">wew</span>
<span id="eg4" style="display: none;">fgd abc wew</span>
</span>
</td>
</tr>
</tbody>
</table>
Here, I want to exclude span element(hidden) having Id of "eg2" and "eg4" from the column filter of yadcf. But whenever I choose an option from select2 it gives me both row as the same text is there in the hidden element.
My JS is as below..
JS:
$(document).ready( function () {
let dataTable = $('#myTable').DataTable();
yadcf.init(dataTable, [{
column_number: 0,
filter_type: 'multi_select',
select_type: 'select2',
column_data_type: 'html',
html_data_type: 'selector',
html_data_selector: 'span:eq(0)',
}], );
});
How can I exclude hidden elements from yadcf column(search) filter? I couldn't get the way how to do it. Please help. Thanks in advance.
JSFIDDLE: https://jsfiddle.net/vjmvj/w5dbtczo/28/