How can i place % symbol after an interger

Question

I need to print a string with an integer an the symbol % after it.

Here is what i try:

sprintf(txt, "%d",CurrentArrayValue,'%');

But my result is only my number. None symbol after that

This should have been covered in just about any beginners book. — Some programmer dude, Feb 07 '18 at 08:11
@Someprogrammerdude: I'd wager that in a room containing 100 reasonably proficient C programmers, only 50 would know this. — Bathsheba, Feb 07 '18 at 08:11
@Bathsheba -- that can't possibly be true; or if it is, I am scared for our future. — ad absurdum, Feb 07 '18 at 08:12
@DavidBowling: I fear it is: and they will be funding our pensions! — Bathsheba, Feb 07 '18 at 08:13
@Bathsheba - Even if it is true, I consider part of true proficiency to be the ability to look it up. — StoryTeller - Unslander Monica, Feb 07 '18 at 08:13
@StoryTeller: You have a point, I used to refer to my library of C and C++ books (and a dusty FORTRAN one too) prior to t'internet. — Bathsheba, Feb 07 '18 at 08:14
I would not even have bothered to look it up and just used a '%c' to add the extra char. — Martin James, Feb 07 '18 at 10:13

score 0 · Answer 1 · answered Feb 07 '18 at 08:10

0

sprintf(txt, "%d%%",CurrentArrayValue);

This will do the trick.

From standard §7.21.6.1 C11 standard N1570

A % character is written. No argument is converted. The complete conversion specification shall be %%.

answered Feb 07 '18 at 08:10

user2736738

Bathsheba · Accepted Answer · 2018-02-07T08:15:24.003

0

Use, simply a %% in the format string:

sprintf(txt, "%d%%",CurrentArrayValue * 100);

Your '%' is ignored by sprintf since your formatting string indicates to the function that only one additional argument is needed.

You have to multiply CurrentArrayValue by 100 yourself by the way: I slipped that in to the function parameter list.

edited Feb 07 '18 at 08:15

answered Feb 07 '18 at 08:10

Bathsheba

2 Answers2