Printing '%' with printf in C/C++

Question

Possible Duplicate:
How to escape the % (percent) sign in C's printf

How can I print '%' in C?

E.g.:

printf("A: %.2f%", pc);

...fails, the compiler complains there is an invalid conversion. Of course an easy way is;

printf("A: %.2f%c", pc, '%');

But it's rather inelegant...

I looked on the web, but I didn't find any escape sequence for %. I thought % would work, but it doesn't.

Answer 1

printf("A: %.2f%%", pc);

Answer 2

Just double the '%' in the format string and it will print '%'.

Answer 3

For future printf reference, type:

man 3 printf

on any Linux command prompt. It can do a lot of crazy stuff that most people just aren't aware of.

Answer 4

%% will output % using printf. Check the example at the end of page here