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i'm a total freshman in python, i have 2.7 version on my computer. I need to download latest revision from repository. My code is:

import pysvn 
svn_url = "https://..."
    client = pysvn.Client()

how should i login there? I could not find any information about it.

Evgenia Kotova
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1 Answers1

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By defining a call back function to the SVN client

def svn_login (realm, username, may_save):  
  return True, svn_login_name, svn_login_password, False

client = pysvn.Client ()  
client.callback_get_login = svn_login

Check that: How to catch login failures with PySVN?

Community
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Rami
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  • all time i tried this i have " svn: E235000: In file 'C:\Win32Svn\SVN-1.8.1-24\src-1.8.1\subversion\libsvn_subr\dirent_uri.c' line 1571: assertion failed (! svn_path_is_url(relative))" – Evgenia Kotova Oct 14 '13 at 07:51
  • hang on, will try it :) – Rami Oct 14 '13 at 07:59
  • Worked fine for me. Check the version of your pysvn library and also the SVN version which the library is built against. – Rami Oct 14 '13 at 08:04