How can I print the '%' symbol?

Question

Possible Duplicate:
How to escape the % (percent) sign in C's printf

I want to print the % symbol like this: "8%2F16"

How can I print this string?

did you read the manual before posting here, search on the web for `printf` or something like that? — Jens Gustedt, Aug 17 '12 at 18:31

pb2q · Accepted Answer · 2012-08-17T18:04:44.493

4

If you're trying to print using printf, you'll need to use %%: escape the % with another %:

printf("8%%2F16");

% is an escape character with a special meaning in the printf format string, and so itself needs to be escaped if you're trying to print it.

edited Aug 17 '12 at 18:04

answered Aug 17 '12 at 17:56

pb2q

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score 3 · Answer 2 · answered Aug 17 '12 at 18:06

3

Besides using %%, you can also use %c:

printf("8%c2F16\n", '%');

The %c trick is a good fallback if you can't remember how to escape a character properly in your string. (Although, off the top of my head, the only tricky ones are " and %.)

answered Aug 17 '12 at 18:06

jxh

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What is that code? A Unicode codepoint? Can you add some kind of reference? – Peter Mortensen May 16 '21 at 20:24
@PeterMortensen I think I understand what you are asking now. The reference is the question that was asked. – jxh May 17 '21 at 02:26

score 2 · Answer 3 · answered Aug 17 '12 at 17:58

2

With the suitable escape sequence, like so: printf("%%");

(Or of course just as puts("%");, but I suppose you're talking about formatted output.)

answered Aug 17 '12 at 17:58

Kerrek SB

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How can I print the '%' symbol?

3 Answers3