Knowing that
Reads and writes are atomic for all variables declared volatile
Question1: Can this be understood as if
private volatile int x = 0;
x++; operation is atomic?
And that
Marking variable volatile does not eliminate all need to synchronize atomic actions, because memory consistency errors are still possible.
Question2: I wonder under what circumstances (if any) it is possible to see a variable marked volatile and not see any methods of blocks marked synchronized (that attempt to access/ modify the variable)?
In other words, should all variables that need to be protected from concurrent modification be marked volatile?