7

Does Depleted Uranium (DU) have a role in spacecraft shielding?

Crewed spacecraft require shielding to protect crew from hazards of space, particularly:

  1. Micrometors. The chief defense is a Whipple Shield https://en.wikipedia.org/wiki/Whipple_shield consisting of “bumper” layers to break up the micro-meteor before it hits the main shielding layer. This strategy is similar to “air gap armor” used in tanks. DU is incorporated in Abrams tank armor plate due to its high resistance to penetration. DU could be used as the main, inner shielding layer for a Whipple Shield.

  2. Primary cosmic rays are high speed positively charged atomic nuclei including protons. Unfortunately, when primary cosmic particles hit a spaceship hull (or shielding), they produce a spray of secondary particles. Hydrogen (in the form of fuel, water or hydrogen-rich plastic) is the most mass-efficient shielding for cosmic rays.

  3. Gamma rays are high energy electromagnetic radiation. Heavy atomic nuclei (Tungsten, Gold, Lead, and Uranium) are the best shielding materials. Uranium is the most mass-efficient shielding for gamma rays.

Based on this information, I would expect mass-efficient integrated shielding (to protect against micro-meteors, cosmic rays and gamma rays) to consist of:

  1. Spacecraft design utilizing water and fuel storage as shielding, when practical.
  2. Multiple bumper layer Whipple shielding to protect from micro-meteors
  3. Plastic between the Whipple layers to absorb cosmic rays.
  4. An inner layer of depleted uranium to protect from gamma rays and micro-meteor fragments spallated by the Whipple shield.

Depleted uranium is the opposite of “enriched uranium”: it has a lower percentage of the fissile isotope U235, consisting of 99.7% U238 with a half life about the age of the Earth.

Due to its long half life, health hazards of DU are chiefly chemical rather than radiation. It has heavy metal toxicity (similar to lead) with renal, CNS and cardiac toxicity. It has a short elimination half life of 15 days, but can accumulate in internal organs.

Has depleted uranium been considered for radiation shielding in crewed spacecraft beyond LEO?

Woody
  • 21,532
  • 56
  • 146

1 Answers1

17

Is DU, in fact, the best shielding by mass?

The first thing to note is that the given quote from Wikipedia is not very relevant for the case of shielding of spacecraft: It refers to shielding against radiation from radioactive isotopes which is quite different to radiation encountered in space.

In LEO we do have a strong contribution of protons and neutrons in the energy range between 0.1 MeV and 10 MeV which are not generated by radioactive isotopes (outside of fission reactors). To compare the effect of materials against these we need to compare their "nuclear interaction length", e.g. from this table by the Particle Data Group. The relevant values are 50 g/cm² for hydrogen and 200 g/cm² for uranium - you need 4 times as much material if you want to use uranium to shield against neutron and proton radiation. This actually can be understood in a quite simplified view: To stop a proton it needs to hit an atomic nucleus head-on. The single protons of hydrogen are spread rather uniformly across the material. For uranium some nucleons "hide on the backside" of their nucleus and don't provide additional cross-section.

The second important contribution to radiation in space is gamma rays. Here uranium has an advantage because two of the dominant ways for their interaction are the photoelectric effect (which scales with the atomic number to the fourth power: $Z^4$) and pair production that scales with $Z^2$. Here the very strong field of the highly charged nuclei increases the shielding effect substantially. Comparing the "radiation length" value from the table above, uranium is 10 times more efficient than hydrogen in this respect.

The third component of radiation are electrons and positrons, but here the difference between materials is much less pronounced.

Last but not least, it also has to be considered that it's not sufficient to just stop incident particles, the amount and kind of secondary radiation needs to be taken into account as well. E.g. it doesn't help if protons are stopped but produce a nasty mess of radioactive isotopes in the process, e.g. by causing fission of heavy nuclei. In this respect light elements are a clear winner.

asdfex
  • 15,017
  • 2
  • 49
  • 64
  • 2
    Surely the density of the material also plays into it. H2 (solid) is about 0.07 g/cm^3 whereas uranium is about 19 g/cm^3, so much much heavier to lift and less effective at shielding. – bob1 Apr 30 '23 at 21:09
  • 1
    @bob1 I think that "4 times as much material" refers to 4 times the mass per unit area (as expressed in say grams per square centimeter), not 4 times the thickness in linear dimension. In radiation "shieldingology" we frequently (usually) refer to thicknesses in those mass/area units. – uhoh Apr 30 '23 at 21:45
  • @asdfex I totally forgot about protons, which I should not have since (a million years ago) I did a lot of reading on proton spallation as an excellent way to generate lots of interesting and very radioactive isotopes. Very nice answer! – uhoh Apr 30 '23 at 21:49
  • @uhoh I realized the 4x unit was about material, but the fact that U is significantly more massive per unit volume plays heavily into the good 'ol tyranny of the rocket equation, so it's not only that H is better, U is harder to get there in terms of payload. – bob1 May 01 '23 at 00:31
  • @bob1 oh I see (I think) Ya, for many kinds of radiation shielding it's the electrons that do most of the hard work, and every little electron brings along a proton and about one neutron. But the heavy elements (e.g. uranium tantalum) bring roughly another half of a neutrons per electron. Maybe I'm still missing your point; if so just ignore me :-) – uhoh May 01 '23 at 02:31
  • 2
    @uhoh Neutrons are as good as protons when it comes to proton radiation. For gammas "useless neutrons" are outweighed by the powers of the atomic numbers. Stopping neutrons and protons; and high energy gammas by pair conversions needs the nuclei, not the electrons. – asdfex May 01 '23 at 08:54
  • @bob1 A more dense material like uranium should be easier to send to space - a ton of uranium is much more compact and requires a smaller fairing. – asdfex May 01 '23 at 08:57
  • @asdfex but if you are using it as shielding you need to have it spread over the whole capsule = more mass? I don't know much about spacecraft construction, so I don't know the relative volumes needed for H vs U shielding, but I would have thought a solid hydrocarbon with high H content (some sort of plastic, perhaps polyethylene might be suitable), a coating a few cm thick will still be less mass than a coating of U of a mm or so. I'm not talking about sending it as a block with fairing, though there will be a fairing covering it in some form for either type I guess[...] – bob1 May 01 '23 at 09:42
  • [...] @asdfex How much heavier a fairing would be to accommodate the extra volume from the H shielding I don't know; I guess it depends on the additional volume. Having said that, perhaps you need to send a ton of U but only 0.2 ton of H to get the same shielding - I have no idea. – bob1 May 01 '23 at 09:49
  • @bob1 All the numbers above are already in terms of weight per area shielded. Thickness and volume will be quite different, but this doesn't matter much for transportation of solids. – asdfex May 01 '23 at 10:53
  • @asdfex ya it depends on the energies, for 1 MeV photons or 10 MeV protons at least, electrons are fine (but as you point out, those pesky neutrons) but you're right there's a big distribution going much higher in energy and for the photons those high-Z nuclei are really helpful. – uhoh May 01 '23 at 11:39
  • The last paragraph is seems important. I would imagine that depleted uranium, when exposed to cosmic rays, un-depletes itself pretty quickly. – codeMonkey Dec 11 '23 at 21:04