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I am going to be using air coil magnetorquers for a satellite development project. These air coil magnetorquers come embedded in solar panels. I am currently using this magnetorquer , it's a solar panel with a magnetorquer embedded into it. The magnetorquers are going to be used to produce a magnetic moment ($m$) to desaturate the reaction wheels in space. I have a controller that will provide me with the $m$ that I require, but I need a way to experimentally verify that I am getting the correct $m$.

I am pretty familiar with the math behind the ferromagnetic magnetorquers, alot of information is provided by this link.

I mainly have two questions:

Firstly,I am working with the magnetorquers integrated with the solar panels, would the mathematics remain the same? I also know that for normal ferremagnetic magnetorquers , $m=nIA$ , where $m$ is the magnetic dipole moment, $I$ is the current through the magnetorquer and $A$ is the area of the magnetorquer. Are these equations still valid for the air coil magnetorquers?

Secondly, how would I be able to experimentally measure the magnetic dipole moment generated by the air coil? For the ferromagnetic coil magnetoquers, I found this research paper to measure the magnetic dipole moment for a normal ferromagnetic magnetorquer, but I don't know if it would work for an air coil magnetorquer. I am also worried about how the solar panel itself would interfere with the measurements.

Thanks.

John
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  • That's a very nice paper about the ferromagnetic rod magnetotorquer testing. I don't think that that the equation $m=nIA$ applies to a ferromagnetic rod - there's no place to but the permeability or dimensions of the rod. However I think is a good equation to use for your flat coil. I believe that the spec of 1.55$m^2$ in the data sheet represents the product $nA$. If the area of one turn of the PCB trace is roughly 9x9 cm${}^2$ then there are roughy 150 to 200 very narrow turns in the trace, which explains the high DC resistance. – uhoh Oct 16 '16 at 01:26
  • Yeah, I tried using m=nIA to calculate n, the number of turns, and found that it is indeed 1. The datasheet specifies the max m at the max voltage. But in terms of measuring the actual m, would it be already to think of my air coil as a ferromagnetic rod that is pressed flat, and use the same paper that I linked to find m? – John Oct 16 '16 at 01:29
  • No you definitely can't use that equation. It is a (fairly good) approximation for a uniformly magnetized rod of ferromagnetic material, with a permeability $/mu$. The detailed shape of the coil isn't even specified there - it assumes the coil magnetizes the permeable material uniformly. Here you have only a coil and no permeable material. You need math that applies to a flat coil in air. It will also have to be an approximation because this coil has multiple turns of different sizes, and their shape isn't even a perfect square. – uhoh Oct 16 '16 at 01:41
  • So again the best way is to measure at large distance where you can call it a point dipole. – uhoh Oct 16 '16 at 01:41
  • By that you mean measuring the b field at the large distance away from the coil? Wouldn't that be the same as using biot savarts law? Even if I can obtain the B field, how would I calculate the magnetic moment from it? I only have a magnetometer to measure the b field. – John Oct 16 '16 at 01:45
  • Sorry if I'm asking so many questions, I'm really trying to understand it. And of course to solve my problem. – John Oct 16 '16 at 01:45
  • You can use the equation in your previous question and my answer. Since you are measuring an air core coil in air, just use $B=\mu_0H$ with $\mu_0=4\pi \times 10^{-7}$ - the permeability of free space. – uhoh Oct 16 '16 at 01:50
  • Ah, I've actually found this link : http://info.ee.surrey.ac.uk/Workshop/advice/coils/air_coils.html#FDS referring to this link, should I orientated my setup in the same way? In other words prop my solar panel a up and measure the b field at distance X from the center of the coil? – John Oct 16 '16 at 02:11
  • In stackexchange, it is best to stick to asking questions as posted questions, and not to have too many at the same time. It's not perfect but it's the way things work here. – uhoh Oct 16 '16 at 04:02
  • I think it's still relevant isn't it? In the post I've asked how to measure the dipole moment. So inquiring about how to set up the air coil to measure the dipole accurately would still be coherent right? – John Oct 16 '16 at 04:05
  • This is stackexchange, it works so well because it is structured. Maybe you see the message Please avoid extended discussions in comments. appearing? It needs some patience, and some care to write your questions carefully. – uhoh Oct 16 '16 at 04:32
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    Ah, alright. I'll edit my question to make it more concise – John Oct 16 '16 at 05:04

1 Answers1

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See this paper for a good description of how to measure magnetic dipoles. To summarize, the approach is to use a calibrated magnetometer at a fixed distance from the torque rod and back out the dipole from the measured magnetic field. The test should be conducted with as little ferrous material in the test environment as possible. Obviously, the background field must also be subtracted out from the measurement.

As for the equation, the difference between an air core and a magnetic core is reflected in a missing term known as the magnetic permeability, $\mu$, which is a measure of how much the magnetic field is boosted by the presence of the core material.

So your equation is a good approximation for your air-coil, but for an iron-core torque rod you need to account for the core material and geometry as described in the first link.

Adam Wuerl
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  • The paper you linked is the same paper that I have linked in the post. Plus for the solar panels that I have linked, the magnetorquers are embedded in the solar panel. That paper that you've linked only applies for a torque rod. Am I missing something out? ( I've edited the post to include for details for a more complete picture) – John Oct 16 '16 at 17:04
  • Sorry about the duplicate link. I didn't follow all of the links above, I just pasted in the main link from the main paper we use at work. Yes, you’re right to worry about the effect of the solar arrays. I’d recommend testing with no current in the arrays and then repeating the measurement with the arrays illuminated and generating power, as depending on how the array is designed the currents can contribute to the dipole measurement. – Adam Wuerl Oct 16 '16 at 17:12
  • Yeah. My main concern is that they are two totally different types of magnetorquers. Unless I can assume that my current embedded magnetorquer to be a compressed version of the torque rod used in the research paper. Which would mean that I'd have to prop up the solar array on it's side and duplicate the same experiment. Which I am not sure if I can do.

    I can't really apply $m=nIA$ as well, as the no. of turns,$n$, is not provided in the datasheet.

    – John Oct 16 '16 at 17:17
  • Adam, I think it would be good if you could bring in more of the information from your link. – called2voyage Dec 15 '16 at 18:48