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In the long process that resulted in the classification of finite simple groups, some of the exceptional groups were only shown to exist after people had computed (most of) their character tables and other such precise information which usually can only be attached to things that exist. Maybe someone familiar with the details can tell me/us:

Was there at some point a finite simple group conjectured to exist that turned out not to exist in the end?

If so, this part of the story is much less told than the successful part! It would be interesting to know if for such a non-existent group, say, the character table was computed, and so on...

I am asking because I just read this question on Math.SE and it reminded me I have always wanted to know this.

4 Answers4

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There was a point during the history of the Classification when pursuers of sporadic groups distinguished the Baby Monster, the Middle Monster and the Super Monster. The first two actually turned out to exist (though the word "Middle" was dropped), but the third turned out to be a dud.

http://www.neverendingbooks.org/index.php/tag/simples/page/2 has an account of this.

DavidLHarden
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    Good example. I believe that it's the Middle Monster that failed to exist. According to Wikipedia, the automorphism group of Fi${22}$ centralizes an element of order 3 in the baby monster, and there's a triple cover of Fi${24}$ that centralizes an element of order 3 in (what is now called) the monster. There is no analogous fact for Fi$_{23}$. – Timothy Chow Dec 08 '12 at 21:44
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    The permalink would be http://www.neverendingbooks.org/index.php/arnolds-trinities-version-20.html – Harry Altman Dec 08 '12 at 22:23
  • Ah! This is exactly what I wanted. Does the non-existent one exist in a non-groupy way, perchance? – Mariano Suárez-Álvarez Dec 09 '12 at 02:06
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    It seems I remembered correctly.

    https://books.google.com/books?id=Y-mlPuzqWBYC&pg=PA241&lpg=PA241&dq=%22super+monster%22+group&source=bl&ots=P0j4fS_5Fg&sig=ZtvlwZapkaCuYpil-iCxdKLHGNQ&hl=en&sa=X&ei=o1laVam_MMqWNsuRgLAL&ved=0CCcQ6AEwAw#v=onepage&q=%22super%20monster%22%20group&f=false

    – DavidLHarden May 18 '15 at 21:29
  • Links are dead. – darij grinberg Nov 05 '17 at 05:07
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I'm not sure if this is quite what you're looking for but....

In this book "Finite simple groups", Gorenstein tells the story of Feit & Thompson's proof of the odd order theorem. Very roughly, it goes as follows:

Suppose $G$ is a simple group of odd order. Thompson studied the local structure of the group $G$ to obtain information about the structure of the maximal subgroups of $G$. Feit then applied the Brauer-Suzuki theory of exceptional characters to derive a great deal of character-theoretic information about the group $G$. So far so good.

But now they hit a problem. They were seeking, of course, to demonstrate a contradiction. But, as Gorenstein tells it, one of the possible configurations of maximal subgroups & character information proved extremely difficult to disprove. In the spirit of this question, one might say they found an example of a "group that does not exist". In the end, after spending a year being stuck, Thompson managed to demonstrate the required contradiction by a very delicate analysis of the generators and relations of the putative group $G$.

(I don't have a copy of Gorenstein's book with me. If I get chance I might return to this answer so I can provide some quotes. Gorenstein's account of the whole enterprise is really terrific.)

Nick Gill
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  • My question is somewhat vague, because it is difficult to pinpoint exactly what one can mean by «a group was conjectured to exist»; there is a difference between that (whatever it is :-) ) and assuming the group exists to derive a contradiction, as in F&T's proof, though. In the case of the odd order theorem, I think that experts believed the theorem to be true, and had from some time (since Burnside asked the question probably believing the answer was positive) – Mariano Suárez-Álvarez Dec 07 '12 at 21:26
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    Yes `the conjectured to exist' part of your question made me wonder if the FT-theorem was relevant. Still, as Gorenstein tells it, there is a real sense that something awfully like a group was lurking in that final configuration... Maybe a group that wanted to exist but didn't know how :-) – Nick Gill Dec 07 '12 at 21:36
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    Is there a formal sense in which "there is almost such a group"? $:$ (e.g., a binary operation on a set such that associativity fails for exactly one ordered triple of elements, which is otherwise a group) –  Dec 07 '12 at 21:45
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    @Ricky, one possible situation I imagine is that one conjectures there is a group such and such, comes up with a description of its category of modules but which cannot correspond to a group; then it might come from a Hopf algebra, an association scheme, or some other things that resemble groups. – Mariano Suárez-Álvarez Dec 07 '12 at 22:33
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    On p. 212 of Dummit & Foote (3rd ed.), the possibility of a finite simple group of order $3^3 \cdot 7 \cdot 13 \cdot 409$ is discussed, with a certain amount of consistent data for such a group being obtained, but ultimately there can't be such a group since there are no simple groups of odd order. – KConrad Dec 07 '12 at 23:20
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    I'm quite sure I can construct an infinite sequence of simple groups of odd order... – Mark Meckes Dec 08 '12 at 13:08
  • "Suppose G is a simple group of odd order. ... They were seeking, of course, to demonstrate a contradiction." But, there is no contradiction here, unless G is also specified to not be cyclic of prime order, right? – Grant Olney Passmore Dec 08 '12 at 21:23
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    It's common practice among group theorists to omit the locution "except for cyclic groups of prime order" for brevity, understanding that the listener will insert it wherever it is necessary. – Timothy Chow Dec 09 '12 at 00:35
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    @Timothy: I assumed as much, although simply inserting "nonabelian" in the appropriate place strikes me as a better compromise. – Mark Meckes Dec 12 '12 at 20:18
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    A bit more on @KConrad's comment: Dummit & Foote analyzes simple groups of order 168=$2^3\cdot 3\cdot 7$ and of order $3^3\cdot 7\cdot 13\cdot 409$ in parallel. The former exists but the latter doesn't. As Dummit & Foote said in their textbook, the simple group of this particular odd order needs to be ruled out as a small part of the proof of the odd order theorem. Dummit & Foote also outlines a character-theoretic proof of the nonexistence of this group on p.898. – Yuji Tachikawa Jan 14 '20 at 06:47
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I tried to write a longer answer which froze, so I'll write a shorter version. You might look at the history of the "Solomon fusion system" which arose in a characterization problem undertaken by Ron Solomon in his work on the classification of finite simple groups. This does not occur in a finite group, but was shown by Dave Benson to occur in a group like topological object ( "2-adic loop space") called BDI(4).

In some sense this led to work by topologists (especially Broto, Levi and Oliver) on "$p$-local finite groups" (actually topological spaces, not groups) which need to associate a linking system to a fusion system of a finite $p$-group. Aschbacher and Chermak showed in an Annals paper a few years ago that the Solomon fusion system does have an associated linking system, an therefore there is a $2$-local finite group associated to that fusion system. More recently, Chermak has shown that there is a $p$-local finite group associated to every saturated fusion system on a finite $p$-group.

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I believe that at some point there was a conjecture (by whom, I don't recall) that Janko's smallest group, of order $175,560=11(11^2-1)(11^3-1)/(11-1)$, should be the first of an infinite sequence of finite simple groups with a Lie-type group-order formula. Such groups turned out not to exist.