Angle between two planes, finding the second plane

Asked Oct 29 '13 at 14:42

Active Oct 29 '13 at 14:53

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I've got a plane given by $x-y+z=0$ and a line given by $r=(0,0,a)+t(1,1,b)$.

How do I find another plane that contains the line and intersects the other plane at an angle of $45^\circ$?

Is the vector $s=(1,1,b)$ perpendicular to both vectors $n_1$ and $n_2$ of the two planes where $n_1$ and $n_2$ are the normals of the two planes?

edited Jun 12 '20 at 10:38

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asked Oct 29 '13 at 14:42

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How did you come up with the vector $s$? – Mhenni Benghorbal Oct 29 '13 at 15:32
Depending on the line specified, it might not be possible to find such a plane. – abiessu Oct 29 '13 at 15:36

Angle between two planes, finding the second plane

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