2

This question originated from an exercise asking to compare the arclength of $y=x^2$ between $(0,0)$ and $(1,1)$ and $\frac{\pi}{2}$.

The solution starts by constructing the circle with center $(0,1)$ and radius $1$, and showing that the arc of parabola sits entirely within the circle, thus the arclength is less than $\frac{\pi}{2}$.

However, I'm not entirely sure that this is a valid proof, for the last step invokes some geometric intuition and I do not see an obvious way to rephrase it rigorously.

pzq_alex
  • 329

0 Answers0