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It's well known that under some "weak" hypothesis, such as finitely generated, the support of an A-module is closed in Spec(A). It is true also in the most general case?

user26857
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1 Answers1

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Pick a non-closed subset $S$ of $\operatorname{Spec}\mathbb Z$, and let $\displaystyle M=\bigoplus_{\mathfrak p\in S}\:\mathbb Z/{\mathfrak p}$.

user26857
  • 52,094
  • Nice but doesn't seem quite correct to me! What about $S={ (0) }$ ? The generic point is non-closed and you get with your formula $M=\mathbb Z$, whose support is the whole of $\mathbb Z$ obviously, hence closed. To correct this $S$ must contain maximal ideals only. – Niels Nov 27 '14 at 10:47