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When there is an initial change in current, I understand that the inductor resists the change. but how does it eventually give in with the flow of current? can someone give me the nuances of the working of the inductor?

jsotola
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Fredrick
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    Do the answers in How does an inductor store energy? help in understanding the working of an inductor? – Chester Gillon Jan 08 '24 at 20:06
  • it takes time for a magnetic field to change – jsotola Jan 08 '24 at 20:06
  • There can be no initial change in current <-- not without infinite voltage being required or produced. An inductor doesn't give in either; it does what it does very consistently. – Andy aka Jan 08 '24 at 20:35
  • If it does what it does, then why the current flow? eventually doesn't it conduct the current after the inductor is fully charge like a normal conductor? – Fredrick Jan 08 '24 at 20:39
  • If we're talking ideal inductors then an inductor never can get fully charged; it will always continue charging when an ideal DC voltage source is applied to its terminals. – Andy aka Jan 08 '24 at 20:41
  • It's hard to visualize what you have described. I agree that you might be right, but can you give me some perspective as to how an ideal inductor behaves. I need it to study the power electronic converters, rectifiers, which uses inductors, inductors are everywhere. – Fredrick Jan 08 '24 at 20:45

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The inductor acts against a change in current. For an ideal step change, i.e. a forcible change of current in no time, the resulting voltage is infinite.

\$V = L \cdot \frac{\Delta I}{\Delta t} \qquad[Volt;Henry;\frac{Amper}{second}]\$

For a finite slope of current over time, you get a finite voltage.

frr
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    An L is missing. – winny Jan 08 '24 at 20:16
  • I understand that. thanks. But the how the inductor's resistance to block the current is overpowered until di/dt becomes zero, is what I want to understand – Fredrick Jan 08 '24 at 20:46
  • @Fredrick You need to start from specifying what is given, and what results. Is the slope of current given, and voltage results? Or, is voltage applied to the coil, and the current slope results? To me, the latter way is easier to understand. Voltage is like "pressure" (a mechanical force) and inductance is like inertia. Have you ever tried to push a heavy loaded cart on flat surface? Or a small merry-go-round with children sitting on it? You apply a mechanical force, and it gradually starts moving. The slope ends when you stop pushing. Stop applying mechanical force. – frr Jan 08 '24 at 20:58
  • Since I am not solving any problem, I can't say what's given. I just want to understand it from a fundamental and deep approach. Yes, that's a very good illustration. thanks – Fredrick Jan 09 '24 at 19:53