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I am looking to have a PCB produced for a personal project of mine. I have to use very thin traces and tight clearances to escape pads on a BGA chip on my board. I was looking at the capabilities of JLCPCB, and noticed that they differentiated between the clearance of a pad to a wire (which they state is 0,2 mm) and clearance of a wire to another wire (which they state is 0,09 mm).

My question is: why are these numbers so wildly different? As far as I understand, they are both just pieces of copper which get selectively etched away. On some forums, I saw some people state that they ignore the pad-to-trace clearance and just take the trace-to-trace clearance. But it makes me wonder why the PCB manufacturer sees the 2 as different things.

I took the clearances from here btw.

elialm
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1 Answers1

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But it makes me wonder why the PCB manufacturer sees the 2 as different things.

It's likely that this is due to the solder mask tolerance.

With two side-by-side tracks, the solder resist unambiguously covers both tracks and acts as reasonable protection.

However, a pad has a "gap" or "hole" (mask) in the solder resist around it and, that will have a significant tolerance. The tolerance could be so much that a close-by track also gets exposed leading to potential shorts when reflowing: -

enter image description here

Image from Sierra circuits.

Andy aka
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