Expressing 2D Gabor transform as 1D spectrum

Question

The Gabor transform (Short-Time Fourier Transform with Gaussian window) is represented as $U(t,\omega)$, where $t$ is the time, and $\omega$ is the frequency. The author of a monograph (Seismic Inverse Q filtering, pg. 190) is asking for the Gabor spectrum to be transformed from 2D to 1D in the following fashion.

1. Define $\chi = \omega t$
2. Take the 2D amplitude spectrum $|U(t,\omega)|$ into a 1D amplitude spectrum as $|U(\chi)|$

The issue that I am struggling with is that $\chi$ is the product of $\omega$ and $t$.

The following Matlab code demonstrates that $\chi$ does not continue to increase monotonically. Note the "sawtooth" appearance of $\chi$.

So how do I take the 2D signal as a 1D signal? For each $\chi$, there should be exactly one $|U(\chi)|$.

N0 = 51;
N1 = 1604;
fs = 1.0e3;
f = (fs/2) * linspace(0,1,N0);
omega = 2 * pi .* f;
dt = 1 / fs;
T = (N1-1) * dt;
t = linspace(0,T,N1);

chi = [];
cnt = 1;
for i = 1:length(omega)
   for j = 1:length(t)
        chi(cnt) = omega(i) * t(j);
        cnt = cnt + 1;
   end 
end

figure;
plot(chi);
xlabel('\chi')
ylabel('Value')

However, the Gabor spectrum is a 2D matrix, similar to this example, where $\omega$ is on one axis, and $t$ is on the other axis:

Answer 1

Equation 11.1 shows the equation for $A$: $$A(\tau,\omega) = A_0 \exp\left(-\frac{\omega \tau}{2Q}\right)$$

We see that $A$ really only depends on the product of $\tau$ and $\omega$, therefore by defining a new variable $\chi = \omega \tau$ we can rewrite this expression as

$$A(\chi) = A_0 \exp\left(-\frac{\chi}{2Q}\right)$$

Perhaps this helps.