Just trying to understand density calculations, for example,
Water has a density of $\pu{0.997 g cm^-3}$ at $\pu{25 ^\circ C}$; ice has a density of $\pu{0.917 g cm^-3}$ at $\pu{-10 ^\circ C}$.
If a soft-drink bottle whose volume is $\pu{2.00 L}$ is completely filled with water and then frozen to $\pu{-10 ^\circ C}$, what volume does the ice occupy?
It depends.... under steady state conditions
If the bottle is glass, then the glass shatters, and the frozen water sublimes so there is no ice left.
If the container can withstand the pressure without distorting and the container volume changes less than $\pu{0.005 L}$ with a temperature change from $\pu{25 ^\circ C}$ to $\pu{-10 ^\circ C}$, then the final volume will be $\pu{2.00 L}$.
If container was so flimsy so that it distorted at a slight change in atmospheric pressure, and it was initially filled completely ($\pu{2.00 L}$) at $\pu{25 ^\circ C}$; then the ice would occupy a volume of: $$\pu{2.00 L} \cdot \frac{\pu{0.997 g cm^3}}{\pu{0.917 g cm^3}}= \pu{2.17 L}$$
If the container distorts, but is pressurized, then the volume will be $$\pu{2.00 L} \le V \le \pu{2.17 L}$$
