I had prepared the sample of Cav2O6 using solid-state reaction route. I had done XRD, SEM-EDS which all matched with the previous results. There was something strange when I did the PL analysis. I saw that most of the vanadates gave the yellow-orange spectra but my sample was giving dark blue. I was not able to find anything related to that in previous researches.
So, I thought that CaV2O6 must also have the properties of CaO as (CaV2O6=CaO-V2O5). I searched the PL studies of CaO and the results were matching closely. So, can I conclude that at a particular excitation wavelength, the properties of CaO component of my sample are more prominent.