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Enol content tautomers

I have figured out that 4 one will have the highest enol content of all, and the 1 structure would come after 4 in enol content, i.e 4 > 1. Then I got confused between the 2nd and the 3rd structures.

Please give a brief explanation for the answer as well.

andselisk
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    What are the factors that determine enol formation? Is it easier to deprotonate an Ester or a ketone? Those are the sort of questions you need to consider – PCK Jun 13 '19 at 19:24

1 Answers1

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Enol content in 3 is greater then enol content of 2

Greater the acidic nature of alpha Hydrogen,greater is the tendency for Tautomeric behavior. H at alpha position in ketone is more acidic then H at alpha position in an ester.Pka values are shown below.The withdrawing power of ester is less compared to carbonyl group in ketone. Since lone pair on oxygen is in conjugation with C=O in ester,its withdrawing power decreases(as shown below).A more acidic α-hydrogen implies a weaker C−H bond. Summarizing,the enol content increases with the acidity of the enolic hydrogen.

$$\ce{carbonyl <=> enol}$$ $$\mathrm{K_{eq}=\frac{[enol]}{[carbonyl]}}$$

The equilibrium between keto and enol form is tipped to enol if H at alpha carbon is more acidic.

Hence enol content in 3 is greater then enol content of 2.

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Pka of cyclohexanone is as per this link: https://www.drugbank.ca/drugs/DB02060

Enol of 4th compound is aromatic and should be most stable.

Therefore extent of enol content must be 4>1>3>2. As a general guide line the following can be used for predicting enol content.

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The enol form of cyclohexanone has bond angles around double bond other then 120${^o}$ as shown below using avagadro.

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Chakravarthy Kalyan
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